Zabbix 4.0 - 飞书告警Python脚本
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Zabbix 4.0 - 飞书告警Python脚本

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2022-04-16 / 0 评论 / 102 阅读 / 正在检测是否收录...

Zabbix 4.0 - 飞书告警Python脚本

#!/usr/bin/python3
import requests
import json
import sys
import os
import datetime

# webhook地址粘贴进url内
url = "webhook地址"


def send_message(message):
    payload_message = {
        "msg_type": "text",
        "content": {
            "text": message
        }
    }
    headers = {
        'Content-Type': 'application/json'
    }

    response = requests.request("POST", url, headers=headers, data=json.dumps(payload_message))
    return response


if __name__ == '__main__':
    text = sys.argv[1]
    send_message(text)
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